Given a stream of integers and a window size, calculate the moving average of all integers in the sliding window.

Implement the MovingAverage class:

• MovingAverage(int size) Initializes the object with the size of the window size.
• double next(int val) Returns the moving average of the last size values of the stream.

Example 1:

Input

["MovingAverage", "next", "next", "next", "next"]
[[3], [1], [10], [3], [5]]

Output

[null, 1.0, 5.5, 4.66667, 6.0]

Explanation

MovingAverage movingAverage = new MovingAverage(3);
movingAverage.next(1); // return 1.0 = 1 / 1
movingAverage.next(10); // return 5.5 = (1 + 10) / 2
movingAverage.next(3); // return 4.66667 = (1 + 10 + 3) / 3
movingAverage.next(5); // return 6.0 = (10 + 3 + 5) / 3

Constraints:

• 1 <= size <= 1000
• -10⁵ <= val <= 10⁵
• At most 10⁴ calls will be made to next.

/**
 * @param {number} size
 */
var MovingAverage = function(size) {
    this.n = size;
    this.queue = [];
    this.average = 0.0;
};

/** 
 * @param {number} val
 * @return {number}
 */
MovingAverage.prototype.next = function(val) {
    var removedVal;
    if(this.queue.length >= this.n) {
        removedVal = this.queue.shift();
        this.average = this.average - removedVal;
    }

    this.queue.push(val);
    
    this.average += val;
    console.log(this.average / this.queue.length);
    return this.average / this.queue.length;
};


var movingAverage = new MovingAverage(3);
movingAverage.next(1); // return 1.0 = 1 / 1
movingAverage.next(10); // return 5.5 = (1 + 10) / 2
movingAverage.next(3); // return 4.66667 = (1 + 10 + 3) / 3
movingAverage.next(5); // return 6.0 = (10 + 3 + 5) / 3